3/2w^2=96

Solution for 3/2w^2=96 equation:

3/2w^2=96

We move all terms to the left:

3/2w^2-(96)=0


Domain of the equation: 2w^2!=0

w^2!=0/2

w^2!=√0

w!=0

w∈R


We multiply all the terms by the denominator


-96*2w^2+3=0

Wy multiply elements

-192w^2+3=0

a = -192; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-192)·3
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-192}=\frac{-48}{-384}
=1/8
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-192}=\frac{48}{-384}
=-1/8
$